Class 8MathematicsUnderstanding QuadrilateralsFind the angle measure of x, y, ...

Find the angle measure of x, y, z and w in the given figures.  

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(a) Sum of all angles of triangle = 180°

One side of triangle = 180°- (90° + 30°) = 60°

x + 90° = 180° ⇒ x = 180° – 90° = 90°

y + 60° = 180° ⇒ y = 180° – 60° = 120°

z + 30° = 180° ⇒ z = 180° – 30° = 150°

x + y + z = 90° + 120° + 150° = 360°

(b) Sum of all angles of quadrilateral = 360°

One side of quadrilateral = 360°- (60° + 80° + 120°) = 360° – 260° = 100°

x + 120° = 180° ⇒ x = 180° – 120° = 60°

y + 80° = 180° ⇒ y = 180° – 80° = 100°

z + 60° = 180° ⇒ z = 180° – 60° = 120°

w + 100° = 180° ⇒ w = 180° – 100° = 80°

x + y + z + w = 60° + 100° + 120° + 80° = 360°

दी गई आकृतियों में x, y, z और w के कोणों का मान ज्ञात कीजिए।  

img_68e26614469506.30280339.jpeg

(a) त्रिभुज के सभी कोणों का योगफल = 180°  

त्रिभुज का एक कोण = 180° – (90° + 30°) = 60°  

Now,  
x + 90° = 180° ⇒ x = 180° – 90° = 90°  
y + 60° = 180° ⇒ y = 180° – 60° = 120°  
z + 30° = 180° ⇒ z = 180° – 30° = 150°  

Thus,  
x + y + z = 90° + 120° + 150° = 360°  

∴ मान हैं:  
x = 90°, y = 120°, z = 150°  

(b)  चतुर्भुज के सभी कोणों का योगफल = 360°  

चतुर्भुज का एक कोण = 360° – (60° + 80° + 120°) = 100°  

Now,  
x + 120° = 180° ⇒ x = 180° – 120° = 60°  
y + 80° = 180° ⇒ y = 180° – 80° = 100°  
z + 60° = 180° ⇒ z = 180° – 60° = 120°  
w + 100° = 180° ⇒ w = 180° – 100° = 80°  

Thus,  
x + y + z + w = 60° + 100° + 120° + 80° = 360°  

∴ मान हैं:  
x = 60°, y = 100°, z = 120°, w = 80°